***BOGO*** Re: [Mingw-users] ANSI escape sequences problem

[Giel van Schijndel <me@xxxxxxxxx>]

Bengt Werstén schreef:
> > -----Original Message-----
> > From: mingw-users-bounces@xxxxxxxxxxxxxxxxxxxxx [mailto:mingw-users-bounces@xxxxxxxxxxxxxxxxxxxxx] On Behalf Of JonY
> > Sent: den 24 juni 2008 09:02
> > To: MinGW Users List
> > Subject: Re: [Mingw-users] ANSI escape sequences problem
> >
> > Bengt Werstén wrote:
> > > Using the simple program:
> > >
> > > #include <stdlib.h>
> > > #include <stdio.h>
> > >
> > > int main(void)
> > > {
> > > const unsigned char back[] = {0x1b, '[', 'D', '\0'};
> > > printf("12%s34", back);
> > > return 0;
> > > }
> > >
> > > It do not give the same result when executed from cygwin bash depending if
> > > built using mingw or not.
> > >
> > > $ gcc main.c
> > > Results in printing 134 when run and this is expected since the escape
> > > sequence should result in a cursor left.
> > >
> > > $ gcc -mno-cygwin main.c
> > > Results in 12←[D34 being printed when run but I would like it to have the
> > > same result as above.
> > >
> > > Is there anyway around this since I need to use MinGW with this
> > > behavior? I have tried out output methods like write and putc but it is
> > > still the same result.
> > This is due to the fact that the Windows console does not understand 
> > the escape sequence. This is not really a MinGW problem. Not too sure 
> > how to resolve it without resorting to 3rd party programs. 
> Hmm, does I not matter at all that I run both programs from the same bash shell in cygwin?
>   
AFAIK the version compiled with Cygwin (i.e. *without* -mno-cygwin) uses 
a different I/O library which emulates the behaviour of a terminal that 
supports ANSI control sequences. The version compiled without Cygwin 
(i.e. *with* -mno-cygwin) links with Windows' native C library, which 
doesn't emulate a proper ANSI terminal in Windows' console, thus the 
difference. Thus the shell that you happen to use doesn't matter.

I expect that running the Cygwin version in Windows' native "dos-like" 
shell (cmd.exe) would give you the same behaviour.

Either way, this is mainly an educated guess, but you can test it like I 
mentioned above.

PS Please don't top-post.

--
Giel

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